![]() + CASE WHEN DATEPART(SECOND, a.EndDate - a.StartDate) > 0 THEN CAST( DATEPART(SECOND, a.EndDate - a. The default precision is 3, meaning a milliseconds precision current time will be returned. Constructs a TIME object using a DATETIME object. If no time zone is specified, the default time zone, UTC, is used. It supports an optional parameter to specify a time zone. Constructs a TIME object using a TIMESTAMP object. As a function, CURRENTTIME () accepts precision as an optional parameter for rounding the second fractional digits (nanoseconds). We can specify intervals when performing arithmetic against dates and times. Constructs a TIME object using INT64 values representing the hour, minute, and second. + CASE WHEN DATEPART(MINUTE, a.EndDate - a.StartDate) > 0 THEN CAST( DATEPART(MINUTE, a.EndDate - a.StartDate) AS nvarchar( 100)) + ' Minutes ' ELSE ' ' END Description: Returns the time when the current query reached the server. + CASE WHEN DATEPART(HOUR, a.EndDate - a.StartDate) > 0 THEN CAST( DATEPART(HOUR, a.EndDate - a.StartDate) AS nvarchar( 100)) + ' Hours ' ELSE ' ' END + CASE WHEN DATEPART(DAY, a.EndDate - a.StartDate) > 1 THEN CAST( DATEPART(DAY, a.EndDate - a.StartDate) - 1 AS nvarchar( 100)) + ' Days ' ELSE ' ' END ![]() + CASE WHEN DATEPART(MONTH, a.EndDate - a.StartDate) > 1 THEN CAST( DATEPART(MONTH, a.EndDate - a.StartDate) - 1 AS nvarchar( 100)) + ' Months ' ELSE ' ' END Remove 0 elements from the output SELECT CASE WHEN DATEPART(YEAR, a.EndDate - a.StartDate) > 1900 THEN CAST( DATEPART(YEAR, a.EndDate - a.StartDate) - 1900 AS nvarchar( 100)) + ' Year ' ELSE ' ' END ![]() Let's have a look at this using an example: This introduces complexity in the calculation since in each date part, the previous date part value needs to be taken into account. I want to subtract 'X' days and 'X' minutes from sysdate, where the days and minutes are an integer as input parameter. In other words, if you choose the interval to be minutes a difference is expressed in minutes even if the difference is greater than a single hour. I have a time field in my database, it has the value 22:05. DATEDIFF calculates the whole difference between two dates. There are a ton of examples how to calculate the difference for two datetime values using DATEDIFF function. INSERT INTO #TextualDateDiffTest (StartDate, EndDate) Insert test data INSERT INTO #TextualDateDiffTest (StartDate, EndDate)
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